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Q. An unbiased cubic die marked with $1,2,2,3,3,3$ is rolled 3 times. The probability of getting a total score of 4 or 6 is

Probability - Part 2

Solution:

$ 1,2,2,3,3,3$ (thrown 3 times)
$P (1) =\frac{1}{6} ; P (2)=\frac{2}{6} ; P (3)=\frac{3}{6} $
$P ( S ) = P (4 \text { or } 6)= P (112(3 \text { cases }) \text { or } 123(6 \text { cases }) \text { or } 222) $
$ =3 \cdot \frac{1}{6} \cdot \frac{1}{6} \cdot \frac{2}{6}+6 \frac{1}{6} \cdot \frac{2}{6} \cdot \frac{3}{6}+\frac{2}{6} \cdot \frac{2}{6} \cdot \frac{2}{6}=\frac{6+36+8}{216}=\frac{50}{216}=\frac{25}{108} $