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Q. An oxide of metal have $20\%$ oxygen, the equivalent weight of oxide is:

Some Basic Concepts of Chemistry

Solution:

$20g$ of $O_{2}$ in $80g$ metal
$8g$ of $O=\frac{80}{20}\times 8g$ metal or $32g$ metal
Equivalent weight of oxide $= E_{metal}+ E_O = 32 + 8 = 40$