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Q. An organic liquid, $A$, is immiscible with water. When boiled together with water, the boiling point is $90^{\circ} C$ at which the partial vapour pressure of water is $526\, mm\, Hg$. The atmospheric pressure is $736\, mm\, H g$. The weight ratio of the liquid and water collected is $2.5: 1$. What is the molecular weight of the liquid?

Solutions

Solution:

$\frac{ P _{ L }}{ P _{ H _{2} O }}=\frac{ n _{ L }}{ n _{ H _{2} O }}$
$\frac{736-526}{526}=\frac{ W _{ L } / M _{ L }}{ W _{ H _{2} O } / 18}$
$\frac{210}{526}=\frac{2.5}{ M _{ L }} \times 18$
$M _{ L }=112.7\, gm$