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Q.
An organic compound weighing $0.15\, g$ gave on Carius estimation, $0.12\, g$ of $AgBr$. The percentage of Br in the compound will be close to (At. mass of $Ag = 108, Br = 80$)
COMEDKCOMEDK 2015Organic Chemistry – Some Basic Principles and Techniques
Solution:
Percentage of bromine in the compound
$ = \frac{80}{188} \times \frac{\text{Mass of AgBr formed}}{\text{Mass of substance taken}} \times 100$
$ = \frac{80}{188} \times \frac{0.12}{0.15} \times 100 = 34.04\%$