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Q. An organic compound on analysis gave $C = 54.2\%, H = 9.2\%$A by mass. Its empirical formula is

Some Basic Concepts of Chemistry

$C H O_{2}$

$CH_{2}O$

25%

$C_{2}H_{8}O$

12%

$C_{2}H_{4}O$

56%

Solution:

Element % No. of Moles Mole ratio Whole no. ratio

C 54.2 54.2/12=4.5 4.5/2.3=2 2

H 9.2 9.2/1=9.2 9.2/2.3=4 4

O 36.6 36.6/16=2.3 2.3/2.1=1 1

Empirical Formula $= C_{2}H_{4}O$

Element	%	No. of Moles	Mole ratio	Whole no. ratio
C	54.2	54.2/12=4.5	4.5/2.3=2	2
H	9.2	9.2/1=9.2	9.2/2.3=4	4
O	36.6	36.6/16=2.3	2.3/2.1=1	1