Q. An organic compound $C_6H_{12}\, (X)$ on reduction gives $C_6H_{14}\, (Y)$. $X$ on ozonolysis gives two aldehydes $C_2H_4O \,(I)$ and $C_4H_8O \,(II)$. Identify the compounds $X$, $Y$ and aldehydes $(I)$ and $(II)$.
Hydrocarbons
Solution:
Correct answer is (a) $X = CH_3CH = CHCH_2CH_2CH_3$,
$Y=CH_3(CH_2)_4CH_3$,
$(I) = CH_3CHO$, $(II) = CH_3(CH_2)_2CHO$
