Question

An organic compound $A$ upon reacting with $NH_{3}$ gives $B$. On heating, $B$ gives $C$. $C$ in presence of $KOH$ reacts with $Br_{2}$ to give $CH_{3}CH_{2}NH_{2}$ . $A$ is

• A.
• B. $CH_{3}CH_{2}CH_{2}COOH$
• C. $CH_{3}COOH$
• D. $CH_{3}CH_{2}COOH$

Answer 1

Answer: (D)

$\underset{A}{C H_{3} C H_{2} C O O H}+NH_{3} \rightarrow \underset{B}{C H_{3} C H_{2} C O_{2} N H_{4}}\xrightarrow{ \Delta }\underset{C}{C H_{3} C H_{2} C O N H_{2}}$
$\xrightarrow{ KOH + \left(Br\right)_{2} \text{Hoffmann Bromamide reaction}) }\left(CH\right)_{3}\left(CH\right)_{2}\left(NH\right)_{2}+H_{2}O$