Question

An organic compound $(A)$ reacts with sodium metal and forms $(B)$. On heating with conc. $H _{2} SO _{4},(A)$ gives diethyl ether. $(A)$ and $(B)$ are respectively

• A. $C _{2} H _{5} OH$ and $C _{2} H _{5} ONa$
• B. $C _{3} H _{7} OH$ and $CH _{3} ONa$
• C. $CH _{3} OH$ and $CH _{3} ONa$
• D. $C _{4} H _{9} OH$ and $C _{4} H _{9} ONa$.

Answer 1

Answer: (A)

$C _{2} \underset{(A)}{H _{5}} OH \xrightarrow{ Na}C _{2} \underset{(B)}{H _{5}} ONa$

$2 C _{2} \underset{(A)}{H _{5}} OH \xrightarrow{ H _{2} SO _{4}} \underset{\text{Diethyl ether}}{C _{2} H _{5}- O - C _{2} H _{5}}$