Q. An organic compound $'A'$ has the molecular formula $C_3H_6O$, it undergoes iodoform test. When saturated with dil. $HCl$ it gives $'B'$ of molecular formula $C_9H_{14}O$. $A$ and $B$ respectively are
VITEEEVITEEE 2019
Solution:
The compound A with formula $C_3H_6O$ gives iodoform test, it is propanone. It forms a compound B having carbon atoms three times to the number of carbon atoms in propanone, it is 2, 6-dimethyl-2, 5-heptadien-4-one

