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Q.
An organ pipe is closed at one end has fundamental frequency of $1500\, Hz$. The maximum number of overtones generated by this pipe which a normal person can hear is:
Waves
Solution:
Critical hearing frequency for a person is $20,000\, Hz$.
If a closed pipe vibration in $N$ th mode then frequency of vibration
$n=\frac{(2 N-1) v}{4 l}=(2 N-1) n_{1}$
(where $n_{1}=$ fundamental frequency of vibration)
Hence $20,000=(2 N-1) \times 1500$
$\Rightarrow N=7.1=7$
Also, in closed pipe Number of over tones
$=$ (No. of mode of vibration) $-1$
$=7-1=6$