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Q. An opera glass (Galilean telescope) measures $9 \,cm$ from the objective to the eyepiece. The focal length of the objective is $15 \,cm$. Its magnifying power is

Ray Optics and Optical Instruments

Solution:

$f_{o}-f_{e}=9 \,cm$ and
$f_{e}=f_{o}-9=15-9=6 \,cm$
$\Rightarrow m=\frac{f_{e}}{f_{e}}=\frac{15}{6}=2.5$