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Q. An open vessel at $27^{\circ}C$ is heated until two fifth of the air (assumed as an ideal gas) in it has escaped from the vessel. Assuming that the volume of the vessel remains constant, the temperature at which the vessel has been heated is :

JEE MainJEE Main 2019States of Matter

Solution:

$\frac{2}{5}$air escaped from vessel, $\therefore \, \frac{3}{5} \, $air remain
is vessel , P, V constant
$ \, \, \, n_1T_1 \, = \, n_2 T_2$
$n_1 (300) \, = \, \bigg(\frac{3}{5} \, n_1\bigg)T_2 \, \Rightarrow \, T_2 \, =500 K$