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Q. An open pipe resonates to a frequency $'f_{1}'$ and closed pipe resonates to a frequency $'f_{2}'.$ If they are joined together to form a longer tube. Then it will resonate to a frequency of (Neglect end correction

NTA AbhyasNTA Abhyas 2020

Solution:

$f_{1}=\frac{V}{2 \ell _{1}}$ $\ell _{1}=\frac{V}{2 f_{1}},\ell _{2}=\frac{V}{4 f_{2}}$
$f=\frac{V}{4 \ell }$ $f=\frac{V}{4 \left[\frac{V}{2 f_{1}} + \frac{V}{4 f_{2}}\right]}$ $\boxed{f = \frac{f_{1} f_{2}}{f_{1} + 2 f_{2}}}$