1. Tardigrade
  2. Question
  3. Physics
  4. An oil drop having a mass of 4.8 × 10-10 g and charge of 30 × 10-18 C stands still between two charged horizontal plates separated by a distance of 1 cm. If now polarity of the plates is changed, instantaneous acceleration of the drop is ( g =10 m / s 2)

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An oil drop having a mass of $4.8 \times 10^{-10} g$ and charge of $30 \times 10^{-18} C$ stands still between two charged horizontal plates separated by a distance of $1 cm$. If now polarity of the plates is changed, instantaneous acceleration of the drop is $\left( g =10 m / s ^{2}\right)$

Electric Charges and Fields

Solution:

Case I : when oil drop is in equilibrium
image
$\therefore mg = qE$
case II : when the polarity are reversed
image
$mg + qE = ma$
$mg + mg = ma$
$2 mg = ma$
$2 g = a$
$2 \times 10 = a$
$a = 20m/s^2$