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Q. An observer moves towards a stationary source of sound, with a velocity one-fifth of the velocity of sound. What is the percentage increase in the apparent frequency?

NTA AbhyasNTA Abhyas 2022

Solution:

$f_{app}=f_{0}\left(\frac{v + v_{0}}{v}\right)$
$\frac{f_{app} - f_{0}}{f_{0}}=\frac{v_{0}}{v}=\frac{\frac{v}{5}}{v}=\frac{1}{5}=20\%$