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  4. An observer moves towards a stationary source of sound with a velocity that is one-fifth the velocity of sound. The apparent change in frequency is

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Q. An observer moves towards a stationary source of sound with a velocity that is one-fifth the velocity of sound. The apparent change in frequency is

Odisha JEEOdisha JEE 2011Waves

Solution:

When the observer is moving towards a stationary source
Apparent frequency $v' = v \left[ \frac{v + v_0}{v}\right]$
$v' = v \left[ \frac{v + \frac{v}{5}}{v}\right]$
or $v' = \frac{6}{5} v $
$\therefore $ Change in frequency $ = \frac{6}{5} v - v $
$= \frac{1}{5} v $
$\therefore \%$ change $= 20\%$