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Q. An object of weight $W$ has a uniform rectangular cross section of $a\times 2a$ and density of $0.25gcm^{- 3}$ . Part of it is immersed in water and the rectangle is tilted by $45^{^\circ }$ , while one of its corners is just at the water surface. Calculate the torque of the buoyancy force with respect to center of mass of the object.
Question

NTA AbhyasNTA Abhyas 2022

Solution:

$\mathrm{W}=$ buoyancy force
Consider the center of mass and symmetry of immersed part
of the object.
$r=\frac{1}{4} \sqrt{a^{2}+a^{2}}=\frac{a}{2 \sqrt{2}}$
$\tau=W r=\frac{a W}{2 \sqrt{2}}$