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  4. An object of mass 10 Kg moves at a constant speed of 20 m / s. A constant force, that acts for 5 second on the object gives it a speed 2 m / s in opposite direction. The force acting on the object is:

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Q. An object of mass $10 Kg$ moves at a constant speed of 20 $m / s$. A constant force, that acts for $5$ second on the object gives it a speed $2 m / s$ in opposite direction. The force acting on the object is:

Motion in a Straight Line

Solution:

As we know that,
$v = u +\text { at }, v =-2 m / s , u =20 m / s $
$(-ve\, sign) =$ opposite direction
$\frac{ v - u }{t}= a$
$\frac{-2-20}{5}= a \Rightarrow \frac{-22}{5}= a$
Force $= ma =10 \times \frac{-22}{5}=-44 N$