Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An object of mass $1\, kg$ moving on a horizontal surface with initial velocity $8\, m/s$ comes to rest after $10\,s$. If one wants to keep the object moving on the same surface with velocity $8\, m/s$ the force required is

Laws of Motion

Solution:

To find the frictional force offered by the ground
$v=u +a t$
$v=0$
$0=8-\mu g(10)$
$\mu=\frac{8}{100}=0.08$
To move the body with constant velocity on this surface, internal force applied should be equal to friction force, $F =\mu mg$
$=(0.08)(1)(10)=0.8\, N$