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Q.
An object is placed at the focus of concave lens having focal length $f$. What is the magnification and distance of the image from the optical centre of the lens?
JEE MainJEE Main 2021Ray Optics and Optical Instruments
Solution:
$U =- f$
$\frac{1}{ V }-\frac{1}{ U }=\frac{1}{- f } $
$\Rightarrow \frac{1}{ V }=-\frac{2}{ f }$
$V =\frac{- f }{2}$
$m =\frac{ V }{ U }=\frac{1}{2}$
distance $=\frac{ f }{2}$