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  4. An object is placed at a distance 20 cm from the pole of a convex mirror of focal length 20 cm . The image is produced at

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Q. An object is placed at a distance $ \, 20 \, cm$ from the pole of a convex mirror of focal length $20 \, cm$ . The image is produced at

NTA AbhyasNTA Abhyas 2022

Solution:

$u \, = \, -20 \, cm, \, f= \, 20 \, cm$
From mirror formula,
$\frac{1}{f}=\frac{1}{v}+\frac{1}{u}$
$\frac{1}{20}=\frac{1}{v}+\frac{1}{- 20}$
$\frac{1}{v}=\frac{1}{20}+\frac{1}{20}$
$\frac{1}{v}=\frac{2}{20}\Rightarrow v \, = \, 10 \, cm$