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Q. An object is moving in positive direction till time t and then turns back with the same negative acceleration. The velocity time graph which best describes the situation is:

Motion in a Straight Line

Solution:

Here, we observe that the object is moving in positive direction till time $t=0$ to $t=t_{1}$ and at $t=t_{1}$ we find that the velocity become negative i.e., the object changes its direction at $t=t_{1}$ and continues in negative direction hence forth. For acceleration we can observe that throughtout the journey the slope of the v-t curve is negative and hence, acceleration is negative. Thus, the area under the $v-t$ curve gives displacement.
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