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Q. An object is lying at a distance of $90\, cm$ from a concave mirror of focal length $30\, cm$. The position and nature of image formed by it will be

Solution:

$v =\frac{ uf }{ u - f }=\frac{-30 \times-90}{-90+30}$
$=-\frac{30 \times 90}{60}=-45\, cm ($ Real $)$
$m =-\frac{ v }{ u }=-\left[\frac{-45}{-90}\right]=-\frac{1}{2}$ (small size)