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Physics
An object is kept at a distance of 60 cm from a concave mirror. For getting a magnification of (1/2), focal length of the concave mirror required is
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Q. An object is kept at a distance of $60\,cm$ from a concave mirror. For getting a magnification of $\frac{1}{2}$, focal length of the concave mirror required is
KEAM
KEAM 2012
Ray Optics and Optical Instruments
A
20 cm
0%
B
40 cm
0%
C
- 20 cm
50%
D
30 cm
50%
E
10 cm
50%
Solution:
$ m=-\frac{v}{u} $
$ \frac{1}{2} =-\frac{v}{60} $
$ v =-30\,cm $
$ \frac{1}{f} =\frac{1}{v}-\frac{1}{u} $
$ \frac{1}{f} =\frac{1}{-30}+\frac{1}{-60} $
$ \frac{1}{f} =-\frac{-2-1}{60}=\frac{-3}{60} $
$ f=-20 \,cm$