Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An object is at a temperature of $ 400{}^\circ C $ . At what temperature would it radiate energy twice as fast? The temperature of the surroundings may be assumed to be negligible

Rajasthan PETRajasthan PET 2001

Solution:

In first state, $ E=\sigma {{(673)}^{4}} $ In second state, $ 2E=\sigma {{T}^{4}} $ $ \therefore $ $ \frac{1}{2}={{\left( \frac{673}{T} \right)}^{4}} $ $ T={{(2)}^{1/4}}\times 673=800\,K $