Thank you for reporting, we will resolve it shortly
Q.
An object is allowed to fall from a height $R$ above the earth, where $R$ is the radius of earth. Its velocity when it strikes the earth's surface, ignoring air resistance, will be
Loss in PE = Gain in KE
$ \left(-\frac{ GMm }{2 R }\right)-\left(-\frac{ GMm }{ R }\right)=\frac{1}{2} mv ^2 $
$ \Rightarrow v ^2=\frac{ GM }{ R }= gR$
$ \Rightarrow v =\sqrt{ gR }$