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Q. An LCR series circuit of capacitance $62.5\, nF$ and resistance of $50\, \Omega$. is connected to an A.C. source of frequency $2.0\,kHz$. For maximum value of amplitude of current in circuit, the value of inductance is ___$mH$.
(Take $\left.\pi^2=10\right)$

JEE MainJEE Main 2023Alternating Current

Solution:

$ f =\frac{1}{2 \pi \sqrt{ LC }} $
$ 2000\, Hz =\frac{1}{2 \pi \sqrt{ L \times 62.5 \times 10^{-9}}}$
$ L =\frac{1}{4 \pi^2 \times 2000^2 \times 62.5 \times 10^{-9}}=0.1 H =100\, mH $