1. Tardigrade
  2. Question
  3. Physics
  4. An L C R circuit contains resistance of 100 Ω and a supply of 200 V at 300 rad angular frequency. If only capacitance is taken out from the circuit and the rest of the circuit is joined, current lags behind the voltage by 60°. If, on the other hand, only inductor is taken out, the current leads by 60° with the applied voltage. The current flowing in the circuit is

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Q. An $L C R$ circuit contains resistance of $100\, \Omega$ and a supply of $200\, V$ at $300 \,rad$ angular frequency. If only capacitance is taken out from the circuit and the rest of the circuit is joined, current lags behind the voltage by $60^{\circ}$. If, on the other hand, only inductor is taken out, the current leads by $60^{\circ}$ with the applied voltage. The current flowing in the circuit is

Alternating Current

Solution:

According to the given question,
$ \tan 60^{\circ}=\frac{\omega L}{R} \text { and } \tan 60^{\circ}=\frac{1 / \omega C}{R}$
$\therefore \omega L=(1 / \omega C)$( case of resonance)
Now $ Z=\sqrt{R^{2}+\left(\omega L-\frac{1}{\omega C}\right)^{2}}=100 \,\Omega$
$\therefore$ $I_{ rms }=\frac{E_{ rms }}{Z}=\frac{200 \,V }{100 \,\Omega}=2 \,A$