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Q.
An iron rod of length $L$ and magnetic moment $M$ is bent in the form of a semicircle. Now its magnetic moment will be
Magnetism and Matter
Solution:
On bending a rod its pole strength remains unchanged whereas its magnetic moment changes.
New magnetic moment $M'=m(2 R)=m$
$\left(\frac{2 L}{\pi}\right) \equiv \frac{2 M}{\pi}$
