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  4. An ionic compound AB has ZnS type structure, if the radius A + is 22.5 pm, then the ideal radius of B is

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Q. An ionic compound $AB$ has $ZnS$ type structure, if the radius $A ^{+}$ is $22.5\, pm$, then the ideal radius of $B$ is

Solution:

Since ionic compound $AB$ has $ZnS$ type structure, therefore it has tetrahedral holes, for which,
$\frac{\text { Radius of cation }}{\text { Radius of anion }}=0.225$
$\frac{r_{+}}{r_{-}}=0.225$
$\frac{22.5}{r_{-}}=0.225$
Hence, $r_{-}=100 \,pm$