Question

An inductor of $1 \,H$ is connected across a $220 \,V, \,50\, Hz$ supply. The peak value of the current is approximately

• A. 0.5 A
• B. 0.7 A
• C. 1 A
• D. 1.4 A

Answer 1

Answer: (C)

Current $\left(i_{0}\right)=\frac{E_{0}}{X_{L}}$
$\Rightarrow i_{0}=\frac{E_{0}}{L \omega}$
$\therefore i_{0}=\frac{220 \times \sqrt{2}}{1 \times 2 \pi \times 50}$
$\Rightarrow i_{0}=\frac{220 \times \sqrt{2}}{100 \pi}=\frac{220 \times \sqrt{2}}{100 \times 3.14}$
$\Rightarrow i_{0}=1 A$