Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An inductive circuit contains resistance of $10 \,\Omega$ and an inductance of $20\, H .$ If an AC voltage of $120\, V$ and frequency $60\, Hz$ is applied to this circuit, the current would be nearly

Alternating Current

Solution:

$i=\frac{V}{\sqrt{R^{2}+\omega^{2} L^{2}}}$
$=\frac{120}{\sqrt{100+4 \pi^{2} \times 60^{2} \times 20^{2}}}=0.016 A$