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  4. An individual homozygous for genes cd is crossed with wild type and F1 crossed back with the double recessive. The appearance of the offspring is as follows + + → 903 cd → 897 +d → 98 c+ → 102 The distance between the genes c and d is

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Q. An individual homozygous for genes cd is crossed with wild type and F1 crossed back with the double recessive. The appearance of the offspring is as follows
+ + → 903
cd → 897
+d → 98
c+ → 102
The distance between the genes c and d is

NTA AbhyasNTA Abhyas 2020Principles of Inheritance and Variation

Solution:

% 𝑜𝑓 𝑟𝑒𝑐𝑜𝑚𝑏𝑖𝑛𝑎𝑡𝑖𝑜𝑛 = 𝐷𝑖𝑠tan𝑐𝑒 𝑏𝑒𝑡𝑤𝑒𝑒𝑛 𝑡𝑤𝑜 𝑔𝑒𝑛𝑒𝑠
= $\frac {𝑇𝑜𝑡𝑎𝑙 \,𝑛𝑜. \,𝑜𝑓 \,𝑟𝑒𝑐𝑜𝑚𝑏𝑖𝑛𝑎𝑛𝑡\, 𝑝ℎ𝑒𝑛𝑜𝑡𝑦𝑝𝑒𝑠}{𝑇𝑜𝑡𝑎𝑙\, 𝑛𝑜. \,𝑜𝑓 \,𝑝𝑟𝑜𝑔𝑒𝑛𝑦 \, \times 100 } \times 100 $
= 200 $\times$ 1002000 = 10 % 𝑜𝑟 10 𝑐𝑀