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Q. An inclined plane making an angle $60^{\circ}$ with the vertical. A ring is rolling down this inclined plane from rest without slipping has an acceleration equal to

System of Particles and Rotational Motion

Solution:

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$a=\frac{g \sin \theta}{1+\frac{K^{2}}{R^{2}}}=\frac{g \times \frac{1}{2}}{1+1}$
$=\frac{g}{2 \times 2}=\frac{g}{4}$