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Q. An ideal solution was obtained by mixing methanol and ethanol. If the partial vapour pressure of methanol and ethanol in solution are $2.619 \,kPa$ and $4.556 \,kPa$ respectively, the composition of vapour (in terms of mole fraction) will be :

Solutions

Solution:

$P_{\text {Total }}=2.619+4.556=7.175 kPa$

$X_{ MeOH }=\frac{P_{ MeOH }}{P_{\text {Total }}}=\frac{2.619}{7.175}=0.365$

$X_{\text {EtOH }}=1-0.365=0.635$