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Q. An ideal gas expands in volume from $ 1\times {{10}^{-3}}{{m}^{3}} $ to $ 1\times {{10}^{-2}}{{m}^{3}} $ at 300 K against a constant pressure of $ 1\times {{10}^{5}}N{{m}^{-2}}. $ The work done is

Jharkhand CECEJharkhand CECE 2010

Solution:

Work done due to change in volume against constant pressure, $ W=-p({{V}_{2}}-{{V}_{1}}) $ $ =-1\times {{10}^{5}}N{{m}^{-2}}(1\times {{10}^{-2}}-1\times {{10}^{-3}}){{m}^{3}} $ $ =-900Nm=-900\,J $ $ (1\,Nm=1J) $