Tardigrade
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Chemistry
An ideal gas expands in volume from 1×10-3 m3 to 1×10-2 m3 at 300 K against a constant pressure of 1×105 Nm-2. The work done is
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Q. An ideal gas expands in volume from $1×10^{-3} m^3$ to $1×10^{-2} m^3$ at $300\, K$ against a constant pressure of $1×10^5\, Nm^{-2}$. The work done is
AIEEE
AIEEE 2004
Thermodynamics
A
-900 J
46%
B
900 kJ
19%
C
2780 kJ
15%
D
-900 kJ
19%
Solution:
Work done $= -P(ΔV)$
$= - 1×10^5 [10^{-2} - 10^{-3}] = - 900\, J$