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Q. An ideal gas at atmospheric pressure is adiabatically compressed so that its density becomes $32$ times of its initial value. If the final pressure of gas is $128$ atmospheres, the value of ‘$\gamma$’of the gas is :

JEE MainJEE Main 2013Thermodynamics

Solution:

Volume of the gas
$v=\frac{m}{d}$ and
using $pV^{\gamma} =$ constant
$\frac{P'}{P}=\frac{V}{V '}=\left(\frac{d '}{d}\right)^{\gamma} $
or $128 = \left(32\right)^{\gamma}$
$\therefore \gamma=\frac{7}{5}=1.4$