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Q. An iceberg is floating partially immersed in sea water. The density of sea water is $1.03\, g\, cm ^{-3}$ and that of ice is $0.92\, g\, cm ^{-3}$. The approximate percentage of total volume of iceberg above the level of sea water is

Mechanical Properties of Fluids

Solution:

$(V-\Delta V) \times 1.03 \times g=V \times 0.92 \times g$
or $\frac{V-\Delta V}{V}=\frac{0.92}{1.03}$
or $\frac{\Delta V}{V}=1-\frac{0.92}{1.03}=\frac{0.11}{1.03}$
or $\frac{\Delta V}{V} \times 100=\frac{11}{1.03} \approx 11$