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  4. An ice-cube of density 900 kg / m 3 is floating in water of density 1000 kg / m 3. The percentage of volume of ice-cube outside the water is

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Q. An ice-cube of density $900\, kg / m ^{3}$ is floating in water of density $1000\, kg / m ^{3}$. The percentage of volume of ice-cube outside the water is

JIPMERJIPMER 2005

Solution:

The percentage of volume of ice cube outside the water is
$=\frac{\rho_{\text {water }}-\rho_{\text{ice}}}{\rho_{\text {water }}} \times 100$
$=\frac{1000-900}{1000} \times 100$
$=10\%$