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  4. An ice-cube of density 900 text kg/m3 is floating in water of density 1000 text kg/m3 . The percentage of volume of ice-cube outside the water is

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Q. An ice-cube of density $ 900\text{ }kg/{{m}^{3}} $ is floating in water of density $ 1000\text{ }kg/{{m}^{3}} $ . The percentage of volume of ice-cube outside the water is

JamiaJamia 2012

Solution:

The percentage of volume of ice cube outside the water is $ =\frac{{{\rho }_{water}}-{{\rho }_{ice}}}{{{\rho }_{water}}}\times 100 $ $ =\frac{1000-900}{1000}\times 100=10% $