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  4. An f.c.c. crystal contains how many atoms in each unit cell ?

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Q. An f.c.c. crystal contains how many atoms in each unit cell ?

AIPMTAIPMT 1996The Solid State

Solution:

$N = \frac{N_{c}}{8} + \frac{N_{f}}{2}+N_{i} $
$ = \frac{8}{8}+\frac{6}{2}+0$
$ = 1+3 = 4$