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  4. An excess of AgNO3 is added to 100 mL of a 0.01 M solution of dichlorotetraaquachromium(III) chloride. The number of moles of AgCl precipitated would be :

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Q. An excess of $AgNO_3$ is added to $100 \,mL$ of a $0.01\, M$ solution of dichlorotetraaquachromium(III) chloride. The number of moles of $AgCl$ precipitated would be :

NEETNEET 2013Coordination Compounds

Solution:

$AgNO_3 + [Cr(H_2O)_4 Cl_2 ]Cl \rightarrow AgCl$
Excess mole = $MV_{(ilt)}$
$ = 0.01 \times \frac{100}{1000}$
$ = 0.001$