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Q. An even periodic function $f: R \rightarrow R$ with period 4 is such that
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The value of $\{ f ( x )\}$ at $x =5.12$ (where \{\} represents fractional part), is

Relations and Functions - Part 2

Solution:

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$\text { At } x =5.12 \Rightarrow f ( x )= x -4 $
$\text { Now } f (5.12)=5.12-4=1.12$
$\therefore \{ f (5.12)\}=0.12=\{ f (7.88)\}$