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Q. An ester $A \left( C _{4} H _{8} O _{2}\right)$, on treatment with excess methyl magnesium chloride followed by acidification, gives an alcohol $B$ as the sole organic product. Alcohol $B$, on oxidation with $NaOCl$ followed by acidification, gives acetic acid. Ester $A$ is:

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Solution:

The given ester reacts with excess of Grignard reagent forms $2$-propanol as a single alcohol product. $2$-propanol on oxidation with $NaOCl$, gives acetic acid and chloroform(It is a haloform reaction). The reaction are shown below,
Solution