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Physics
An equilateral prism deviates a ray through 45° for two angles of incidence differing by 20° . The angles of incidence are :
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Q. An equilateral prism deviates a ray through $45^\circ $ for two angles of incidence differing by $20^\circ $ . The angles of incidence are :
NTA Abhyas
NTA Abhyas 2022
A
$60^\circ $ and $40^\circ $
B
$50^\circ $ and $70^\circ $
C
$62^\circ 30'$ and $42^\circ 30'$
D
$60^\circ 30'$ and $40^\circ 30'$
Solution:
$\delta = \text{i}_{1} + \text{i}_{2} - \text{A}$
$4 5^{^\circ } = \text{i}_{1} + \text{i}_{2} - 6 0^{^\circ }$
$\text{i}_{1} + \text{i}_{2} = 1 0 5^{^\circ }$
$\text{i}_{1} - \text{i}_{2} = 2 0^{^\circ }$
or $2 \text{i}_{\text{i}} = 1 2 5^{^\circ }$
$\text{i}_{1} = 6 2^{^\circ } 3 0^{'} \text{, } \text{i}_{2} = 4 2^{^\circ } 3 0^{'}$