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Q. An engine pumps water continuously through a hose. Water leaves the hose with velocity $v$ and $m$ is mass per unit length of the water jet. If this jet hits a surface and came to rest instantaneously, the force on the surface is

AIEEEAIEEE 2012

Solution:

Rate of kinetic energy
$KE =\frac{ d }{ dt } \frac{1}{2} Mv ^2 $
$\text { But } M = mL $
$KE =\frac{1}{2} \frac{ dm }{ dt } Lv ^2=\frac{1}{2} mv ^3$