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Q. An ellipse is drawn by taking the length of a diameter of the circle $(x-1)^2+y^2=1$ as its semi-minor axis and length of diameter of the circle $x^2+(y-2)^2=4$ as its semi-major axis. If the centre of ellipse is at origin and its axes are the coordinate axes, then eccentricity of ellipse is

Conic Sections

Solution:

Here, $\quad a =4, b =2 \Rightarrow e ^2=1-\frac{4}{16}=\frac{12}{16}=\frac{3}{4} \Rightarrow e =\frac{\sqrt{3}}{2}$