1. Tardigrade
  2. Question
  3. Physics
  4. An elevator of mass 500kg is to be lifted up at a constant velocity of 0.4ms- 1 . What should be the minimum horse power of the motor to be used? (Take g=10ms- 2 and 1hp=750 watts .:-

Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. An elevator of mass $500kg$ is to be lifted up at a constant velocity of $0.4ms^{- 1}$ . What should be the minimum horse power of the motor to be used? (Take $g=10ms^{- 2}$ and $1hp=750$ watts $\left.:-$

NTA AbhyasNTA Abhyas 2020

Solution:

$P=F\cdot v=mgv=500\times 10\times 0.4W$ $=2000W$
$=\frac{2000}{750}hp=\frac{8}{3}hp$