1. Tardigrade
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  3. Physics
  4. An elevator can carry a maximum load of 1800 kg (elevator + passengers) is moving up with a constant speed of 2 ms -1. The frictional force opposing the motion is 4000 N. Determine the minimum power delivered by motor to the elevator.

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Q. An elevator can carry a maximum load of $1800\, kg$ (elevator + passengers) is moving up with a constant speed of $2\, ms ^{-1}$. The frictional force opposing the motion is $4000 \,N$. Determine the minimum power delivered by motor to the elevator.

Work, Energy and Power

Solution:

The downward force on the elevator is $F=m g+F_{f}=(1800 \times 10)+4000=22000 N$. The motor
must supply enough power to balance this force. Hence, $P=\bar{F} \cdot \bar{v}=22000 \times 2=44000 W$